How do you solve #\frac { y } { 8} + 14= 15#?

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Answer 1 · 2017-02-15T12:59:52

See the entire solution process below:

Step 1) Subtract #color(red)(14)# from each side of the equation to isolate the #y# term while keeping the equation balanced:

#y/8 + 14 - color(red)(14) = 15 - color(red)(14)#

#y/8 + 0 = 1#

#y/8 = 1#

Step 2) Now, multiply each side of the equation by #color(red)(8)# to solve for #y# while keeping the equation balanced:

#color(red)(8) xx y/8 = color(red)(8) xx 1#

#cancel(color(red)(8)) xx y/color(red)(cancel(color(black)(8))) = 8#

#y = 8#