How do you solve #-2-6-:(-2)+4#?

1 Answer
Jim G.
Feb 11, 2017

#5#

Explanation:

When evaluating expressions with #color(blue)"mixed operations"# there is a particular order that must be followed.

Follow the order as set out in the acronym PEMDAS

[Parenthesis ( brackets), Exponents (powers),Multiplication, Division, Addition / Subtraction ]

#rArr-2-6/(-2)+4#

#=-2+3+4larrcolor(red)" division before add/subtract"#

We are left with only Addition and evaluate from left to right.

#rArr-2+3+4=5#

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