Question #4c66a Chemistry Thermochemistry Calorimetry 1 Answer JuliaKim Feb 9, 2017 See below: Explanation: Using your formula (with a slight correction): #Q = mc∆t + mLf + mc∆t + mLv + mc∆t# #Q = (0.025)(2100)(0+15) + (0.025)(3.3 * 10^5) + (0.025)(4180)(100-0) + (0.025)(2.3 * 10^6) + (0.025)(2000)(130-100)# #Q = 787.5 + 8250 + 104500 + 57500 + 1500# #Q = 172 537.5 J# #Q = 170 000 J# with rounding Answer link Related questions How does differential scanning in calorimetry work? What information do you get from a differential scanning calorimetry plot? How do you measure calorimetry? Question #962a7 Question #1dfc5 Question #41af6 What is calorimetry? What is a differential scanning calorimeter? How can a calorimeter measure energy? What are calorimeters made of? See all questions in Calorimetry Impact of this question 2464 views around the world You can reuse this answer Creative Commons License