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How do you write standard form of quadratic equation of vertex (2,3) and yint = 11?

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1 Answer

Feb 4, 2017

Write the equation in vertex form and then simplify to get standard form.

#y = 2x^2-8x+11#

Explanation:

Write in vertex form
#y = a(x-h)^2 + k#
#y = a(x-2)^2 + 3#

Use y intercept to find constant #a#:
#11 = a*4 + 3#
#a = 2#

Rewrite and simplify with #a=2#:

#y = 2(x-2)^2 + 3#
#y = 2* (x^2-4x+4)+3#
#y = 2x^2-8x+11#

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