How do you add #\frac { 12y } { y ^ { 2} + 16y + 48} + \frac { 6} { y + 4}#?

1 Answer
Annie
Feb 2, 2017

#(6(y+14))/((y+4)(y+12))#

Explanation:

#12/(y^2+16y+48)+6/(y+4)#
Factorise
#12/((y+4)(y+12))+6/(y+4)#

So to get a common denominator multiply numerator and denominator of the second term by y+12

#=12/((y+4)(y+12))+6/(y+4)*(y+12)/(y+12)#

#=(12+6(y+12))/((y+4)(y+12))#
#=(12+6y+72)/((y+4)(y+12))#
#=(6y+84)/((y+4)(y+12))#
#=(6(y+14))/((y+4)(y+12))#

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