How do you solve `2( m + 3) = - ( 4m + 12)`?

`2(m+3)=-(4m+12)`

`:.2m+6=-4m-12`

`:.2m+4m=-6-12`

`:.6m=-18`

`:.m=-18/6`

`:.m=-3`

sustitute m`=-3`

`2((-3)+3)=-(4(-3)+12)`

`2 xx 0=-(-12+12)`

`2 xx 0=-(0)`

`0=0`

Let's focus first on the left side of the equation. Multiply 2 by both `m` and `3`. The equation becomes...
`2m + 6 = -(4m + 12)` .

Now on to the right side, multiply that "`-`" or the negative sign to both `4m` and `12`. Think of it as multiplying `-1` to those numbers. The equation becomes...
`2m + 6 = -4m - 12` .

It is time to combine like terms. First, we add `4m` to both sides of the equation.
`4m + 2m + 6 = -4m - 12 + 4m`.

On the left side of the equation, add `4m` and `2m`. On the right side, adding `4m` and `-4m` cancels each other out, that is, the answer is equal to `0`. The equation becomes...
`6m + 6 = - 12`.

Now, we'll subtract `6` on both sides of the equation. It is similar to the previous step but we are subtracting instead. The equation becomes...
`6m = - 18`.

Simplify the equation by dividing 6 on both sides. Divide the like terms and leave out the `m` since it is a variable, not a number. The solution goes like this:
`((6m) / 6) = ((-18) / 6)`.

The answer is now `m = -3`. Hope this helps you.