A circular rug has a radius of #(4x-6)#. What is the area of the rug?

1 Answer
256
Jan 28, 2017

#A=16pix^2-48pix+36pi#

Explanation:

Remember the area of a circle's formula is
#A=pir^2#

In this case #r=(4x-6) => r^2=(4x-6)^2=(4x-6)(4x-6)#

Then using FOIL we get

#r^2=(4x-6)^2=16x^2-48x+36#

Then the area of the rug #A# is

#A=pir^2=16pix^2-48pix+36pi#

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