What is $-3x^4y^2 * -x^0y^-4 * 2x$ ?

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Answer 1 · 2017-01-25T21:53:20

$6x^5y^-2$

Using the property of exponents, that $a^b * a^c = a^(b+c)$ :

$-3x^2y^2 * -x^0y^-4 * 2x = -(-3) * 2 * x^(4 + 1 - 0) * y^(2-4)$

$= 6x^5y^-2$ or $(6x^5)/y^2$ . Note that the minus sign in front of $x^0$ does matter, even if it's attached to $x^0$ , which is equal to $1$ anyway.

What is -3x^4y^2 * -x^0y^-4 * 2x-3x^4y^2 * -x^0y^-4 * 2x?