How do you simplify #4x-2+(-6x)+8#?

Question

3969 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-21T20:28:17

See a solution process below for: 4x + 2 = 6x - 8

First, subtract #color(red)(4x)# and add #color(blue)(8)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#4x - color(red)(4x) + 2 + color(blue)(8) = 6x - color(red)(4x) - 8 + color(blue)(8)#

#0 + 10 = (6 - color(red)(4))x - 0#

#10 = 2x#

Now, divide each side of the fraction by #color(red)(2)# to solve for #x# while keeping the equation balanced:

#10/color(red)(2) = (2x)/color(red)(2)#

#5 = (color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2))#

#5 = x#

#x = 5#

Answer 2 · 2017-01-21T20:29:11

#4x-2+(-6x)+8=-2x+6#

First, since #4x-2=4x+(-2)#

We can say

#4x-2+(-6x)+8=4x+(-2)+(-6x)+8#

Then we group like terms

#4x+(-6x)+(-2)+8=(4x+(-6x))+((-2)+8)#

Then we simplify

#=(4x-6x)+(8-2)=(-2x)+(6)=ul(-2x+6)#