How do you graph #y=ln(x+1)#?

1 Answer
256
Jan 19, 2017

Shift the graph of #ln(x)# to the left by #1#

Explanation:

graph{ln(x+1) [-5, 5, -5, 5]}

Remember that since #ln(x)# and #e^x# are inverse functions #ln(e^x)=x#.

Because if #y=ln(x)# then #y=0# if and only if #ln(x)=0#. Since #e^0=1# then #ln(e^0)=ln(1)=0.# So when we change the function to #y=ln(x+1)#, we have that #y=0=ln(1)=ln(0+1)# So the x-intercept shifts to the left. Just like the x-intercept shift, the entire graph shifts to the left.

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