How do you solve the triangle of $A = 76^{\circ}, a = 18, b = 20$ $A=76^circ, a=18, b=20$ ?

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How do you solve the triangle of $A = 76^{\circ}, a = 18, b = 20$ $A=76^circ, a=18, b=20$ ?

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Answer 1 · 2017-01-11T03:25:39

There is no solution

Explanation:

We attempt to use the law of sines to solve the triangle.
The law states:
$\frac{a}{sin (A)} = \frac{b}{sin (B)} = \frac{c}{sin (C)}$ $a/sin(A) = b/sin(B) = c/sin(C)$

$\frac{18}{sin (76)} = \frac{20}{sin (B)}$ $18/sin(76) = 20/sin(B)$

$20 \cdot sin (76) = 18 \cdot sin (B)$ $20*sin(76) = 18*sin(B)$

$\frac{20}{18} \cdot sin (76) = sin (B)$ $20/18 * sin(76) = sin(B)$

$arcsin (\frac{20}{18} \cdot sin (76)) = B$ $arcsin(20/18 * sin(76)) = B$

$B = arcsin (1.078)$ $B = arcsin(1.078)$

$B =$ $B =$ error

Therefore, there is no solution.

https://www.algebra.com/algebra/homework/Trigonometry-basics/Trigonometry-basics.faq.question.925859.html

https://www.khanacademy.org/math/geometry-home/right-triangles-topic/law-of-sines-geo/v/law-of-sines

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How do you solve the triangle of $A = 76^{\circ}, a = 18, b = 20$ $A=76^circ, a=18, b=20$ ?

1 Answer

Explanation:

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How do you solve the triangle of A=76^circ, a=18, b=20A=76∘,a=18,b=20A=76^circ, a=18, b=20?

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How do you solve the triangle of $A = 76^{\circ}, a = 18, b = 20$ $A=76^circ, a=18, b=20$ ?