How do you solve $\frac{x - 2}{3} + \frac{1}{6} = \frac{5}{6}$ $(x-2)/3+1/6=5/6$ ?

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How do you solve $\frac{x - 2}{3} + \frac{1}{6} = \frac{5}{6}$ $(x-2)/3+1/6=5/6$ ?

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Answer 1 · 2017-01-01T10:33:03

The answer is $x = 4$ $x=4$ , but I show you one way to solve it below.

Explanation:

First, move the $\frac{1}{6}$ $1/6$ term to the right of the = sign, so that terms involving the variable are together on the left and the right side of the equation has only numbers. To do this, subtract $\frac{1}{6}$ $1/6$ from both sidess

$\frac{x - 2}{3} = \frac{5}{6} - \frac{1}{6}$ $(x-2)/3 = 5/6-1/6$

$\frac{x - 2}{3} = \frac{4}{6}$ $(x-2)/3 = 4/6$

Now, get rid of denominators by multiplying each side by 6

#2(x-2)=4

Divide both sides by 2

$x - 2 = 2$ $x-2 = 2$

Add 2 to each side

$x = 4$ $x=4$

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How do you solve $\frac{x - 2}{3} + \frac{1}{6} = \frac{5}{6}$ $(x-2)/3+1/6=5/6$ ?

1 Answer

Explanation:

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How do you solve $\frac{x - 2}{3} + \frac{1}{6} = \frac{5}{6}$ $(x-2)/3+1/6=5/6$ ?