How do you solve #\frac { - 1- 3x } { 4} - \frac { 2x + x } { 6} = \frac { 1} { 3}#?

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Answer 1 · 2016-12-26T05:08:26

#x=-7/15#

#frac(-1-3x)(4)-frac(2x+x)(6)=1/3#

Multiply the equation by the LCD 12.

#12*[frac(-1-3x)(4)-frac(2x+x)(6)=1/3]#

#12/4 * (-1-3x)-12/6*(2x+x)=12/3#

#3(-1-3x) -2(2x+x)=4#

#-3-9x-4x-2x=4#

#-15x-3=color(white)a4#
#color(white)(aaaaa)+3color(white)(a)+3#

#-15x=7#

#(-15x)/-15=7/-15#

#x=-7/15#