How do you solve $- 7 = \frac{v}{3} - 11$ $-7= \frac { v } { 3} - 11$ ?

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Answer 1 · 2016-12-19T01:59:21

$v = 12$ $v=12$

Solve $- 7 = \frac{v}{3} - 11$ $-7=v/3-11$ .

Add $11$ $11$ to both sides.

$- 7 + 11 = \frac{v}{3}$ $-7+11=v/3$

Simplify.

$4 = \frac{v}{3}$ $4=v/3$

Multiply both sides by $3$ $3$ .

$12 = v$ $12=v$

Switch sides.

$v = 12$ $v=12$

Answer 2 · 2016-12-19T02:06:34

$v = 12$ $v=12$

$a^{1} - 7 = \frac{v}{3} - 11$ $color(white)(a^1)-7=v/3 -11$

$a + 11 = a a + 11 a a a$ $color(white)a+11=color(white)(aa)+11color(white)(aaa)$ Add 11 to both sides

$a a a^{1} a 4 = \frac{v}{3}$ $color(white)(aaa^1a)4=v/3$

$a^{1} a 3 \cdot 4 = \frac{v}{3} \cdot 3 a a a$ $color(white)(a^1a)3*4=v/3 *3color(white)(aaa)$ Multiply both sides by 3

$color(white)(a^1a)3*4=v/cancel3 *cancel3$

$color(white)(aa^1aa)12=v$

How do you solve -7= \frac { v } { 3} - 11−7=v3−11-7= \frac { v } { 3} - 11?