How do you solve #3x - 5= 3( x - 1) + 7#?

1 Answer
Teun
Dec 14, 2016

This is an invalid equation with no valid solution for the value of #x# .

Explanation:

You first rearrange the equation for something to equal to x.

#3x -5 = 3(x-1) +7#
#3x = 3x - 3 + 7 + 5#
#3x = 3x + 9#

Then it is found that x is non-existent for this equation because the next step usually to solve this would be:
#0 = 9# which is invalid.

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