Question #0dedf

1 Answer
Dec 12, 2016

7070

Explanation:

Assuming the 88 objects are distinct, then this is equivalent to the number of ways of choosing 44 objects from the group of 88, as if that is the first group, then the remaining 44 is decided as the second group.

The number of ways of choosing kk objects from a set of nn objects can be calculated as

((n),(k)) = (n!)/(k!(n-k)!)

(read as n choose k)

Applying this to the given question, we have the number of ways of choosing a set of 4 objects from a set of 8 as

((8),(4)) = (8!)/(4!(8-4)!)

=(8*7*6*...*3*2*1)/((4*3*2*1)(4*3*2*1)

=(8*7*6*5)/(4*3*2*1)

=70