A zebra starts from rest and accelerates at #1.9# #m##/s^2#. How far has the zebra gone after #5# seconds?
1 Answer
Dec 10, 2016
Using formula dist =
Explanation:
At the end of the first second the zebra is going at 1.9 m/s.
At the end of the second second the zebra is going at 3.8 m/s
...
At the end of the fifth second the zebra is going at (
The zebra's Average Speed was (
Thus in 5 seconds the zebra has travelled (
The basic kinematics formulas to solve such problems is dist =