How do you multiply #3x ( x ^ { - 2} y ^ { 3} )#?

3 Answers
Shaikh A.
Dec 4, 2016

#3y^3x#
to set negative power of x into positive ; put it to the denominator

Explanation:

#3x (x^-2y^3) = 3x(y^3)/x^2 = 3y^3/x#

anor277
Dec 4, 2016

#3x(x^-2y^3)=(3y^3)/x#

Explanation:

#3x(x^-2y^3)=(3x)xxx^-2xxy^3#

#=(3cancelx)xx1/cancel(x)xx1/(x)xxy^3#

#=(3y^3)/(x)# as required.........

Jim G.
Dec 4, 2016

#(3y^3)/x#

Explanation:

Using the #color(blue)"law of exponents"#

#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(a^mxxa^n=a^(m+n)" and " a^-mhArr1/a^m)color(white)(2/2)|)))#

#rArr3x(x^-2y^3)=3x^1xxx^-2xxy^3#

#=3x^(1+(-2))y^3=3x^-1y^3#

#=3xx1/x xxy^3=(3y^3)/xlarr" positive exponents"#

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