How do you order the fractions from least to greatest: $\frac{31}{51}, \frac{12}{17}, \frac{2}{3}$ $31/51, 12/17, 2/3$ ?

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Answer 1 · 2016-11-29T22:04:08

$\frac{31}{51}$ $31/51$ , $\frac{34}{51}$ $34/51$ , $\frac{36}{51}$ $36/51$

$\frac{31}{51}$ $31/51$ , $\frac{12}{17}$ $12/17$ , $\frac{2}{3}$ $2/3$

First find a common denominator in the least amount for all three numbers. [They're the ones on the bottom]

17 and 3 can go into 51, so 51 would be the least all three could go into.

$\frac{31}{51}$ $31/51$ Since the denom is already at 51, you can leave that alone.

$\frac{12}{17}$ $12/17$ If you multiply 17, (the nominator, top number) by 3, you get 51.

What you do to the bottom, you must do to the top.

12 times 3 is 36.

$\frac{12}{17}$ $12/17$ = $\frac{36}{51}$ $36/51$

$\frac{2}{3}$ $2/3$ 3 multiplied by 17 is 51.

Again, doing the bottom, must do the top as well.

2 times 17 is 34.

Making $\frac{2}{3}$ $2/3$ = $\frac{34}{51}$ $34/51$

Now... we order them from L to G.

$\frac{31}{51}$ $31/51$ , $\frac{34}{51}$ $34/51$ , $\frac{36}{51}$ $36/51$

Solution: $\frac{31}{51}$ $31/51$ , $\frac{2}{3}$ $2/3$ , $\frac{12}{17}$ $12/17$

How do you order the fractions from least to greatest: 3151,1217,2331/51, 12/17, 2/3?