How do you solve 10( x - 2) = - 20?

2 Answers
Nov 28, 2016

x=0

Explanation:

Solve 10(x-2)=-20.

Expand the left-hand side using the distributive property, a(b+c)=ab+ac.

10x-20=-20

Add 20 to both sides.

10x=-20+20

10x=0

Divide both sides by 10.

x=0/10

x=0

Nov 28, 2016

x=0

Explanation:

First, multiply 10(x-2). To multiply one number and numbers in parentheses, multiply the one number against every number or term in the parentheses (distributive property ), like this:
3(x^2+10x+2)
=3x^2+30x+6

So, apply it to the problem.
10(x-2)
=10*x+10*(-2)
=10x-20

Now, just simplify. You're trying to get x alone. When you do something to one side of the equation, you must do it to the other. So, add 20 to each side to cancel out the -20 on the x's side.
10x-20=-20
10x-20+20=-20+20
10x=0

Now, divide each side by 10 to get the x alone.
(10x)/10=0/10

x=0