How do you solve #10( x - 2) = - 20#?

2 Answers
Meave60
Nov 28, 2016

#x=0#

Explanation:

Solve #10(x-2)=-20#.

Expand the left-hand side using the distributive property, #a(b+c)=ab+ac#.

#10x-20=-20#

Add #20# to both sides.

#10x=-20+20#

#10x=0#

Divide both sides by #10#.

#x=0/10#

#x=0#

Momo
Nov 28, 2016

#x=0#

Explanation:

First, multiply #10(x-2)#. To multiply one number and numbers in parentheses, multiply the one number against every number or term in the parentheses (distributive property ), like this:
#3(x^2+10x+2)#
=#3x^2+30x+6#

So, apply it to the problem.
#10(x-2)#
#=10*x+10*(-2)#
=#10x-20#

Now, just simplify. You're trying to get x alone. When you do something to one side of the equation, you must do it to the other. So, add 20 to each side to cancel out the -20 on the x's side.
#10x-20=-20#
#10x-20+20=-20+20#
#10x=0#

Now, divide each side by 10 to get the x alone.
#(10x)/10=0/10#

#x=0#

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