Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you evaluate #Sin(π/3)*tan(π/6)#?

1 Answer

Nov 27, 2016

#1/2#

Explanation:

#sin(pi/3)xxtan(pi/6)#
#" "#
#=sqrt3/2xxsqrt3/3#
#" "#
#=sqrt(3^2)/(2xx3)#
#" "#
#=3/(2xx3)#
#" "#
#=1/2#

Related questions

See all questions in Trigonometric Functions of Any Angle

Impact of this question

2521 views around the world

You can reuse this answer
Creative Commons License