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What is the value of the expression #2x^3+3y^2-17# when #x=3# and #y=4#?

1 Answer

Suren Abreu · Anjali G

Nov 22, 2016

The value of the expression is #85#.

Explanation:

#2x^3+3y^2-17#

Substituting #x# with #3# and #y# with #4#, we get:

#2(3)^3+3(4)^2-17#

#2(27)+3(16)-17#

#54+48-17#

#85#

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