How do you use the angle sum or difference identity to find the exact value of #cos((7pi)/12)#?

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How do you use the angle sum or difference identity to find the exact value of #cos((7pi)/12)#?

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Answer 1 · 2016-11-21T21:01:18

#cos(7pi/12)=root2(1/2-root2(3)/4)#

Explanation:

#cos(7pi/12)=cos(pi/2+pi/12)=cos(pi/2)*cos(pi/12)-sin(pi/2)*sin(pi/12)=-sin(pi/12)=-root2((1-cos(pi/6))/2)=-root2((1-roots(3)/2)/2)=-root2(1/2-root2(3)/4)=#

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How do you use the angle sum or difference identity to find the exact value of #cos((7pi)/12)#?

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