How do you find $(6 \times 2) - (19 - [6 \times 3])$ $(6\times 2) - ( 19- [ 6\times 3] )$ ?

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How do you find $(6 \times 2) - (19 - [6 \times 3])$ $(6\times 2) - ( 19- [ 6\times 3] )$ ?

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Answer 1 · 2016-11-21T19:40:53

11

Explanation:

You must do parentheses first and multiplications second so:
$6 x 2 = 12$ $6x2 = 12$ then $6 x 3 = 18$ $6x3 = 18$ so its:
$12 - (19 - 18)$ $12 - (19-18)$
$19 - 18 = 1$ $19-18 = 1$
$12 - (1) = 11$ $12-(1) = 11$

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How do you find $(6 \times 2) - (19 - [6 \times 3])$ $(6\times 2) - ( 19- [ 6\times 3] )$ ?

1 Answer

Explanation:

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How do you find (6×2)−(19−[6×3])(6\times 2) - ( 19- [ 6\times 3] )?

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How do you find $(6 \times 2) - (19 - [6 \times 3])$ $(6\times 2) - ( 19- [ 6\times 3] )$ ?