How do you solve $3 (x - 2) + 9 = - 12$ $3( x - 2) + 9= - 12$ ?

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Answer 1 · 2016-11-16T22:42:23

Use the distributive property.

$3 (x - 2) + 9 = 12$ $3(x-2)+9=12$

Multiple 'x' and -2 by 3.

$3 x - 6 + 9 = 12$ $3x-6+9=12$

Combine like terms.

$3 x + 3 = - 12$ $3x+3=-12$

Get x on one side by subtracting 3 from each side.

$\frac{3 x}{3} = \frac{- 15}{3}$ $(3x)/3 =(-15)/3$

Divide 3x and -15 by 3.

Then you get your answer.

$x = - 5$ $x=-5$

How do you solve 3(x−2)+9=−123( x - 2) + 9= - 12?