Question #f2070

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Answer 1 · 2016-11-07T19:10:31

#(dy)/(dx)=y/(x(yln2-1)#

Use logarithmic differentiation

#xy=2^y#

#ln(xy)=ln(2^y)#

#lnx+lny=yln2#

differentiate with respect to x

#1/x+1/y(dy)/(dx)=ln2(dy)/(dx)#

#(dy)/(dx)(ln2-1/y)=1/x#

#(dy)/(dx)=1/x-:(ln2-1/y)=1/x-:(yln2-1)/y#

#(dy)/(dx)=y/(x(yln2-1)#