How do you solve $\frac { 1} { 7} y + \frac { 1} { 8} y - \frac { 1} { 56} y = y - \frac { 3} { 8}$ ?

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Answer 1 · 2016-11-07T18:25:32

$y = 1/2$

Step 1) Put all like terms over a common denominator.
Step 2) Solve for $y$ while keeping the equation balanced.

$(8/8)1/7y + (7/7)1/8y - 1/56y = 56/56y - 3/8$

$8/56y + 7/56y - 1/56y = 56y/56 - 3/8$

$14/56y = 56/56y - 3/8$

$14/56y - 14/56y + 3/8 = 56/56y - 3/8 - 14/56y + 3/8$

$3/8 = 56/56y - 14/56y$

$3/8 = 42/56y$

$(56/42)3/8 = (56/42)42/56y$

$1/2 = y$

Answer 2 · 2016-11-07T18:59:18

See calculation below.
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How do you solve \frac { 1} { 7} y + \frac { 1} { 8} y - \frac { 1} { 56} y = y - \frac { 3} { 8}\frac { 1} { 7} y + \frac { 1} { 8} y - \frac { 1} { 56} y = y - \frac { 3} { 8}?