What value of #x# satisfies the equation #7/3(x+9/28) = 20#?

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Answer 1 · 2016-11-07T17:25:53

#x = 33/4=8 1/4#

The starting equation is:

#7/3(x+9/28)=20#

The first step is to multiply both sides by #3#:

#7(x+9/28)=60#

Now we divide both sides by #7#

#x+9/28=60/7#

#x=60/7-9/28#

#x=240/28-9/28#

#x=231/28=33/4=8 1/4#