How do you find $f (6)$ $f(6)$ given $f (x) = - \frac{2}{3} x^{2} - x + 5$ $f(x)=-2/3x^2-x+5$ ?

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How do you find $f (6)$ $f(6)$ given $f (x) = - \frac{2}{3} x^{2} - x + 5$ $f(x)=-2/3x^2-x+5$ ?

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Answer 1 · 2016-11-06T18:05:57

-25

Explanation:

All you need to do is plug in 6 for x:

$f (6) = - \frac{2}{3} x^{2} - x + 5$ $f(6)=-2/3x^2-x+5$
$- \frac{2}{3} {(6)}^{2} - (6) + 5$ $-2/3(6)^2-(6)+5$
$- \frac{2}{3} \cdot 36 - 6 + 5$ $-2/3*36-6+5$
$- 24 - 6 + 5 = - 25$ $-24-6+5= -25$

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How do you find $f (6)$ $f(6)$ given $f (x) = - \frac{2}{3} x^{2} - x + 5$ $f(x)=-2/3x^2-x+5$ ?

1 Answer

Explanation:

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How do you find f(6)f(6)f(6) given f(x)=-2/3x^2-x+5f(x)=−23x2−x+5f(x)=-2/3x^2-x+5?

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Explanation:

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How do you find $f (6)$ $f(6)$ given $f (x) = - \frac{2}{3} x^{2} - x + 5$ $f(x)=-2/3x^2-x+5$ ?