Question #fc82b

1 Answer
shr
Oct 31, 2016

From the order #(n, l, m, s)#, the answers are:
#He# = #(1, 0, 0, -1/2)#
#Cl# = # (3, 1, 0, -1/2) #
#C# = #(2, 1, 0, +1/2) #
#S# = #(3, 1, -1, -1/2) #

Explanation:

For a complete explanation on this, check out [this link.](https://socratic.org/chemistry/the-electron-configuration-of-atoms/quantum-numbers)

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