How do you solve $- 9 p - 4 (2 - 4 p) = 2 (p - 3) - 32$ $-9p-4(2-4p)=2(p-3)-32$ ?

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Answer 1 · 2016-10-23T15:28:22

$p = - 6$ $p = -6$

$- 9 p - 4 (2 - 4 p) = 2 (p - 3) - 32$ $-9p - 4(2 - 4p) = 2(p - 3) - 32$

$- 9 p - 8 + 16 p = 2 p - 6 - 32$ $-9p - 8 + 16p = 2p - 6 -32$

$7 p - 8 = 2 p - 38$ $7p - 8 = 2p - 38$

$7 p - 2 p = - 38 + 8$ $7p - 2p = -38 + 8$

$5 p = - 30$ $5p = -30$

$p = - \frac{30}{5}$ $p = -30/5$

$:. p = -6$

How do you solve -9p-4(2-4p)=2(p-3)-32−9p−4(2−4p)=2(p−3)−32-9p-4(2-4p)=2(p-3)-32?