How do you find the coordinates of the center, foci, the length of the major and minor axis given #36x^2+81y^2=2916#?

1 Answer
Oct 15, 2016

You can obtain your answers by doing steps 1 through 4 in the explanation.

Explanation:

Let divide by 2916 and write the denominators as squares:

#x^2/9^2 + y^2/6^2 = 1#

When the denominator of the x term is greater than the denominator of the y term, the standard form is:

#(x - h)^2/a^2 + (y - k)^2/b^2 = 1#

where:

  1. #(h, k)# is the center point
  2. #2a# is the length of the major axis
  3. #2b# is the length of the minor axis
  4. The foci are at #(h + sqrt(a^2 - b^2), k)# and #(h - sqrt(a^2 - b^2), k)#

Subtract zero from x and y to put the equation in standard form:

#(x - 0)^2/9^2 + (y - 0)^2/6^2 = 1#

You can do steps 1 through 4 for your answer.