How do you solve $0.2 (b - 12) = 0.4 b$ $0. 2 ( b - 1 2 ) = 0 . 4 b$ ?

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Answer 1 · 2016-10-12T05:54:28

$- 12$ $-12$

First you should distribute $0.2$ $0.2$ :

$0.2 b - 12 (0.2) = 0.4 b$ $0.2b-12(0.2)=0.4b$

that yields:

$0.2 b - 2.4 = 0.4 b$ $0.2b-2.4=0.4b$

Subtract $0.2 b$ $0.2b$ from both sides:

$- 2.4 = 0.4 b - 0.2 b$ $-2.4=0.4b-0.2b$

$- 2.4 = 0.2 b$ $-2.4=0.2b$

$- \frac{2.4}{0.2} = b$ $-2.4/0.2=b$

$b = - 12$ $b=-12$

Good Luck

How do you solve 0.2(b−12)=0.4b0. 2 ( b - 1 2 ) = 0 . 4 b?