How do you graph #y<(x-2)^2+6#?
1 Answer
Oct 6, 2016
This is vertex form (h,k), with a dotted line and shading below curve
Explanation:
Shade below the curve since it is less than.
Dotted line because there's no equal sign. graph{y<(x-2)^2+6 [-20, 20, -3.12, 16.88]}