How do you graph the exponential function #f(x)=(1/2)^x -3#?

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How do you graph the exponential function #f(x)=(1/2)^x -3#?

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Answer 1 · 2016-10-06T02:00:12

It has a vertical shift of -3. #(1/2)^X# will decrease over time, min of -3 (asymptote), y-int = -2

Explanation:

#(1/2)^x# has a minimum of zero (not including zero), as x approaches infinity, so 0-3 = -3 is a horizontal asymptote graph{(1/2)^x-3 [-10, 10, -5, 5]}

It has a y-intercept of -2 because 1-3 = -2
#(1/2)^0=1#

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How do you graph the exponential function #f(x)=(1/2)^x -3#?

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