What is the standard form of y= (3x^2-x+2)^2-x ?

1 Answer

just square the expression...

Explanation:

y=(3x^2-x+2)^2 -x
y= (3x^2-x+2)(3x^2-x+2)-x
y=3x^2(3x^2-x+2) - x(3x^2-x+2) + 2(3x^2-x+2)-x
y=9x^4-3x^3+6x^2 - 3x^3 +x^2 -2x +6x^2-2x+4-x
y=9x^4-6x^3 + 13x^2-5x+4