What is the equation of the line that goes through $(- 1, - 5)$ $(-1, -5)$ and $(0, 5)$ $(0, 5)$ ?

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What is the equation of the line that goes through $(- 1, - 5)$ $(-1, -5)$ and $(0, 5)$ $(0, 5)$ ?

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Answer 1 · 2016-09-24T11:12:22

$y = 10 x + 5$ $y = color (blue)(10)x +color (red) (5)$

Explanation:

The equation of a straight line can be written in the form

$y = m x + c$ $y = mx + c$

With $x$ $x$ and $y$ $y$ as coordinates, $m$ $m$ as the gradient of the line and $c$ $c$ as the $y$ $y$ intercept (where the line crosses the $y$ $y$ axis).

First we find the gradient, using the equation

$m = \frac{r i s e}{r u n}$ $m = (rise)/(run)$

Rise is the difference in the two $y$ $y$ coordinates and
Run is the difference between the two $x$ $x$ coordinates.

$m = \frac{10}{1}$ $m = (10)/(1)$

$m = 10$ $m = 10$

Now we substitute in the known values into $y = m x + c$ $y = mx + c$ to get

$5 = 10 (0) + c$ $5 = 10(0) + color(red)(c)$

Which is;

$5 = c$ $5 = c$

Therefore the full equation, in the form $y = m x + c$ $y=color (blue)(m)x+color (red)c$ is

$y = 10 x + 5$ $y = color (blue)(10)x +color (red) (5)$

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What is the equation of the line that goes through $(- 1, - 5)$ $(-1, -5)$ and $(0, 5)$ $(0, 5)$ ?

1 Answer

Explanation:

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What is the equation of the line that goes through $(- 1, - 5)$ $(-1, -5)$ and $(0, 5)$ $(0, 5)$ ?