How do you find the inverse of #y= x^2-2x+1# and is it a function?

1 Answer
Monzur R. · Shwetank Mauria
Sep 22, 2016

Inverse function of #y=x^2-2x+1# is #y=sqrtx+1#

Explanation:

#y=x^2-2x+1=(x-1)^2#

#x-1=sqrty#

#x=sqrty+1#

To find the inverse function, #f^-1(x)#, we replace the #x# with #y#. What we've now found is #x=f(y)#, but we want to find #f^-1(x)#. In order to do so, we simply switch #x# with #y#:

#f^-1(x) = sqrtx + 1#

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