How do you solve $| 10 - 8 x | < - 13$ $|10- 8x | < - 13$ ?

Question

1399 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-09-20T19:21:48

No solution.

No solution since the absolute value function can never be negative and hence can never be less than $- 13$ $-13$ .

By definition, $| y | = {(y, y > 0), (- y, y < 0)}$ $|y|={(y, y>0),(-y,y<0)}$

Hence $|y|>=0 AA y in RR$

How do you solve |10- 8x | < - 13|10−8x|<−13|10- 8x | < - 13?