How do you solve $-\frac{8}{7} = \frac{n + 3}{5}$ ?

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Answer 1 · 2016-09-20T14:10:31

try to make denominators equal. then solve the equation...

$-(8*5)/(7*5) = ((n+3)*7)/(5*7)$

$-40/35 = (7n+21)/35$

$-40 = 7n + 21$

$7n = -61$

$n=-61/7$

How do you solve -\frac{8}{7} = \frac{n + 3}{5}-\frac{8}{7} = \frac{n + 3}{5}?