How do you graph #y=-|x+2|#?

1 Answer
Nickel
Sep 13, 2016

graph{-|x+2| [-10, 10, -5, 5]}

Explanation:

graph{x+2 [-10, 10, -5, 5]}

This is #x+2=y# . When there's an absolute value bracket, it means that the y cannot equal to anything below zero (as they turn into a positive number)

So you subsitute 0 into the y to find the roots (the x-intercepts, it's where y=0) and solve for x.

#x+2>= 0#
#x >= -2#

So now we know that the negative part of the graph ( #y<0#) must be reflected when it hits the coordinate (-2,0)

graph{|x+2| [-10, 10, -5, 5]}

This is #|x+2|# . But since the minus sign for #-|x+2|# is on the outside of the equation instead of the inside, it will affect the equation even after the absolute value brackets.

You flip your whole equation along the x-axis for your answer.

Related questions
Impact of this question
5353 views around the world
You can reuse this answer
Creative Commons License