How many #"kg"# of #"C"# atom are in #"3.6 mols"# of #"C"# atom?
↳Redirected from
"Suppose that I don't have a formula for #g(x)# but I know that #g(1)
= 3# and #g'(x) = sqrt(x^2+15)# for all x. How do I use a linear approximation to estimate #g(0.9)# and #g(1.1)#?"
1 Answer
Sep 1, 2016
0.043 kg C.
Explanation:
3.6 mol C *
43.236 g C *
You only need the 6.022 when converting to molecules.
