How do you rationalize the denominator and simplify #sqrt4/sqrt6#?

1 Answer
Jordan W.
Aug 31, 2016

#(sqrt6)/3#

Explanation:

We can start by first realizing that #sqrt4# is really just #2#. So that makes it #2/sqrt6#.

We can take the next step by getting the square root out of the denominator.

#(2/sqrt6)*(sqrt6/sqrt6)# #=# #(2sqrt6)/(sqrt6)^2#.

The squared and square root cancel each other out, leaving just #(2sqrt6)/6#.

Then you can simplify the #2# in the numerator and #6# in the denominator to just get #(1sqrt6)/3#, but you would not write the #1#, so #(sqrt6)/3#.

Related questions
See all questions in Multiplication and Division of Radicals
Impact of this question
1513 views around the world
You can reuse this answer
Creative Commons License