What is the pOH of a #8.4x10^-11 M# #OH^-# solution?

1 Answer
Dr. Hayek
Aug 28, 2016

#pOH=10.08#

Explanation:

The #pOH# of a solution is defined in terms of the concentration of hydroxide ions in solution as follows:

#pOH=-log[OH^(-)]#.

In this question, #[OH^(-)]=8.4xx10^(-11)M#, thus the #pOH# can be calculated by:

#pOH=-log(8.4xx10^(-11))=10.0757~=10.08#

Note that if the concentration is given with 2 significant figures , the #pOH# value is written with two decimal places.

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