How do you solve $6^{x} - 5 = 1$ $6^x-5=1$ ?

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How do you solve $6^{x} - 5 = 1$ $6^x-5=1$ ?

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Answer 1 · 2016-08-23T09:22:57

There are two ways.

Explanation:

You might just realise $6 - 5 = 1$ $6-5=1$ and hence conclude $x = 1$ $x=1$ .
Or ,you move 5 to the other side to get $6^{x} = 6$ $6^x=6$ .
You then take log of both sides ${log 6}^{x} = log 6$ $log6^x=log6$ .
$x log 6 = log 6$ $xlog6=log6$ .
$x = \frac{log 6}{log 6} = 1$ $x=log6/log6=1$ .

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How do you solve $6^{x} - 5 = 1$ $6^x-5=1$ ?

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