How do you solve $- 3 (x + 3) = - 3 (x + 1) - 5$ $-3(x+3)=-3(x+1)-5$ ?

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Answer 1 · 2016-08-19T03:05:00

True for no real values of x

expanding gives -3x - 9 = -3x - 8
This is NOT possible since the equation is not true. The RHS is 1 greater than the LHS. Hence no real solution.

How do you solve −3(x+3)=−3(x+1)−5-3(x+3)=-3(x+1)-5?