How do you factor #36x^2-60x+25#?

2 Answers
Deepak G.
Aug 7, 2016

#=(6x-5)(6x-5)#

Explanation:

#36x^2-60x+25#
#=(6x)^2-2(6x)(5)+5^2#
#=(6x-5)^2#
#=(6x-5)(6x-5)#

Robert C.
Aug 7, 2016

#(6x - 5)^2#

Explanation:

since your #x^2# has a number in front of it, you will need to multiply that by 25 first. this gives you 900 so you now must find two numbers that add to #-60# and multiply to #900#. as luck would have it, #-30# jumps out as the answer. break down the equation accordingly and factor from there.

#36x^2 - 60x + 25#

#36x^2 - 30x - 30x + 25#

factor the frist two variables and then the second two

#36x^2 - 30x - 30x + 25#

#6x(6x - 5) - 5(6x - 5)#

format with the numbers outside the brackets as one group and the leave the others as is.

#(6x - 5)(6x - 5)#

this is a perfect square, ergo

#(6x - 5)^2#

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