Question #82e8d

1 Answer
Owen Bell
Aug 5, 2016

#6# moles of #"CO"_2# are produced.

Explanation:

First, let's consult the formation equation for carbon dioxide from its constituent elements:

#"C"_("(s, graphite)") + "O"_2(g) -> "CO"_2(g)#

As we can see from this equation, the mole ratio of oxygen gas to carbon dioxide gas is #1:1#. This means that the number of moles of these two gases will be equivalent when a reaction goes to completion and the moles of the product to 0.

Thus if the ratio is #1:1#, the ratio is also #6:6# and the output number of moles of #"CO"_2# is #6#.

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