How do you evaluate $a^{2} - 8 a + 5$ $a^2-8a+5$ when $a = 6$ $a=6$ ?

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How do you evaluate $a^{2} - 8 a + 5$ $a^2-8a+5$ when $a = 6$ $a=6$ ?

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Answer 1 · 2016-07-30T23:30:50

-7

Explanation:

You have $a^{2} - 8 a + 5$ $a^2-8a+5$
Substitute $a = 6$ $a=6$ inside all the $a$ $a$ 's.
$6^{2} - 8 (6) + 5$ $6^2-8(6)+5$
Reduce the equation:
$36 - 48 + 5$ $36-48+5$
We get $- 7$ $-7$ .

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How do you evaluate $a^{2} - 8 a + 5$ $a^2-8a+5$ when $a = 6$ $a=6$ ?

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How do you evaluate a2−8a+5a^2-8a+5 when a=6a=6?

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How do you evaluate $a^{2} - 8 a + 5$ $a^2-8a+5$ when $a = 6$ $a=6$ ?