How do you multiply $(4 x + 5) (3 x^{2} - 5)$ $(4x+5)(3x^2-5)$ ?

Question

How do you multiply $(4 x + 5) (3 x^{2} - 5)$ $(4x+5)(3x^2-5)$ ?

1 Answer

Impact of this question

1756 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-27T05:37:45

$12 x^{3} + 15 x^{2} - 20 x - 25$ $12x^3+15x^2-20x-25$

Explanation:

Step 1
I multiplied
$(4 x) 3 x^{2} = 12 x^{3}$ $(4x)3x^2=12x^3$

Step 2
I multiplied
$4 x (- 5) = - 20 x$ $4x(-5)= -20x$

So far we have
$12 x^{3} - 20 x$ $12x^3-20x$

Step 3
I multiplied
$(5) 3 x^{2} = 15 x^{2}$ $(5)3x^2=15x^2$

Step 4
I multiplied
$5 (- 5) = - 25$ $5( -5 )=-25$

We have
$15 x^{2} + 25$ $15x^2+25$

Step 5
In total, we have
$12 x^{3} - 20 x + 15 x^{2} - 25$ $12x^3 - 20x + 15x^2-25$
Final step
We put everything order by powers, since there are no like terms to combine
$12 x^{3} + 15 x^{2} - 20 x - 25$ $12x^3+15x^2-20x-25$

Science

Math

Humanities

... and beyond

How do you multiply $(4 x + 5) (3 x^{2} - 5)$ $(4x+5)(3x^2-5)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you multiply (4x+5)(3x^2-5)(4x+5)(3x2−5)(4x+5)(3x^2-5)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you multiply $(4 x + 5) (3 x^{2} - 5)$ $(4x+5)(3x^2-5)$ ?